Solve the following pair of linear equations: y - 4x= 1 and 6x - 5y= 9 by substitution
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Given equations are y-4x=1 & 6x-5y=9
let's take y-4x=1
=> y = 1 + 4x -------(1)
Now, Substitute 'y' value in 6x-5y=9 from equation (1)
Take 6x-5y=9
=> 6x - 5(1+4x)=9
=> 6x - (5 + 20x ) =9
=> 6x - 5 - 20x = 9
=> (6x - 20x) = 9+5
=> -14x = 14 (or) 14x = -14
=> x = -1
Therefore x = -1
Now, Substitute value of 'x' in equation (1)
equation (1) is y=1+4x
=> y = 1 + 4(-1)
=> y = 1 - 4
=> y = -3
Therefore value of x = -1 & y = -3
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