Question

solve the following pair of linear graphically 2 x minus 3 Y equal to 14 x minus 3 Y + 1 equal to zero that the point 2 and free likes on any one of the like formed by the above given equation​

Answer 1

2x−3y=1

at x=0,y=( -1\3)

and at y=0,x=( 1\2)

so coordinates for line are(0,(-1\3)) and (( 1\2 ),0)

now

4x−3y+1=0

at x=0, y=(1\3)

and at y=0, x=(-1\4)

so coordinates of lines are(0,( 1\3))and(( -1\4),0)