Solve the following pair of linear (simultaneous) equations using method of subsition : 8x+5y=9 and 3x+2y=6
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Answered by
1
Answer:
8x+5y=9 --------(1)
3x+2y=6 -------(2)
multiplying eq 1 by 3
and 2 by 8
24x+15y=27 ------(3)
24x+16y=48 ------(4)
(24x-24x)+(16y-15y)=48-27
y=21
substitute the value of y in eq (1)
8x+5(21)=9
8x+105=9
8x=9-105
8x=-96
x=-12
Hence solution of the equation
x=-12 ,. y=21
subtract equation (3)&(4)
Answered by
1
Answer:
8X+5y=9
3x+2y=6
3(8X+5y)=27
-8(3x+2y)=-48
24x+15y=27
-24x-16y=-48
-y=-21
y=21
now this value put in ist eq
8X+5y=9
8X+5(21)=9
8x+105=9
8x=9-105
8x=96
X=12
so the required solution is {21, 12}
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