Question

solve the following pair of simulataneous equations
2x+3y=8, 3x-y=9​

Answer 1

2x+3y=8 -----(1)

3x-y=9------(2)

Multiplying eqn 1 by 1 and 2 by 3

2x+3y=8

9x-3y=27

--------------

11x = 35

x = 35 / 11

x = 3.18

Substituting x=3.18 in eqn 2

3x-y = 9

3*3.18 -y = 9

9.54 - y = 9

-y = 9-9.54

-y = -0.54

y=0.54

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Answer 2

Answer:

 The value of x is 3.18 and y is 0.54 .

Step-by-step explanation:

Given -

$2x+3y=8\\ 3x-y=9$

To find -

The value of x and y

Solution -

$2x+3y=8 \:\:\:\:\:\:\: (1)\\ 3x-y=9 \:\:\:\:\:\:\: (2)$

To cut any variable in addition the both the number with the variables should be same. If they are not same then multiply second equation and get it same.

Multiply equation (2) by 3 we get

$9x-3y=27 \:\:\:\:\:\: (3)$

Now add equation (1) and (3) we get

$11x = 35$

Divide both side by 11  we get

$x = 3.18$

Put the value of x in equation (1) we get

$2\times3.18 +3y =8$

$6.36 +3y =8$

$3y =8- 6.36$

$3y =1.64$

Divide both side by 3 we get

$y = 0.54$

∴  The value of x is 3.18 and y is 0.54 .