Solve the following pair of simultaneous equations. 8x-3y=16 , 6x-7y=31 .
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Step-by-step explanation:
firs multiple by 6 in eq first and by 8 in equation second
so we get
48x-18y=96
48x-56y=248
no change the sign in equation second
so 48x will cancel out
36y=-152
y= -152/36
now put the value of y in euqal 48x-18y=96
48x-18×-152/36=96
48x -76=96
x=96+76/48
x= 172/48
thesea re the answers for full answer you can solve the values
i hope you'll find it helpful ❤️
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