Question

solve the following pairs of equation by reducing them to a pair of liner equation:-
1) 4/x+3y=14
3/x-4y=23

Answer 1

Heya

∆ To Reduce them to linears :

Take :

$- > \frac{1}{x} = u$

Now,

$4u + 3y = 14$

$3u - 4y = 23$

Solving the above two :

[ Multiply first equation by 3 and second by 4 ]

$12u + 9y = 42$

$12u - 16y = 92$

Now, subtracting both equations from each other :

$25y + 50 = 0$

$= > y = - 2$

And hence, substituting the value of y :

$x = \frac{1}{5}$