solve the following pairs of equations by reducing them to a pair of linear equations. 2/X+3/y=13 and 15/X+y+7/x-y=10where x not equals to 0 ,y not equals to 0 and 5/x-4/y=-2 where X is not equals to 0,y is not equals to 0
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Answered by
1
Answer:
(i)
2x
1
+
3y
1
=2
3x
1
+
2y
1
=
6
13
Lets assume
x
1
=p and
y
1
=q, both equations will become
2
p
+
3
q
=2
⇒3p+2q=12 ... (A)
3
p
+
2
q
=
6
13
⇒2p+3q=13 ...(B)
Multiply (A) by 3 and (B) by 2, we get
9p+6q=36
4p+6q=26
Subtracting these both, we get
5p=10
⇒p=2
⇒x=
p
1
=
2
1
∴q=
6
26−8
=3
⇒y=
q
1
=
3
1
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