Question

solve the following pairs of linear equation by method of substitution 5x-3y=1 , 2x+5y=19

Answer 1

Hii friend,


5X - 3Y = 1........(1)

2X + 5Y = 19--------(2)


From equation (1) we get,

5X - 3Y = 1

5X = 1+3Y

X = 1+3Y/5-------(3)

Putting the value of X in equation (2)

2X + 5Y = 19

2 × (1+3Y/5) + 5Y = 19

2 + 6Y/5 + 5Y = 19

2+6Y + 25Y = 19 × 5

31Y + 2 = 95

31Y = 95-2

31Y = 93

Y = 93/31 = 3

Putting the value of Y in equation (3)

X = 1+3Y/5 = 1 + 3 × 3/5 = 1+9/5 = 10/5

X = 2



HENCE,


X = 2 AND Y = 3



HOPE IT WILL HELP YOU..... :-)