Question

solve the following pairs of linear equation by the substitution and across multiplication method

7(y+3)-2 (x+2)= 14
4(y-2) +3( x-2)=2​

Answer 1

Simplify given equations

7(y+3)−2(x+2)=14

or 7y−2x=−3

and 4(y−2)+3(x−3)=2

or 4y+3x=19

new set of equations is :

7y−2x=−3...(1)

4y+3x=19...(2)

Let us use the elimination method to solve the given system of equation.

Multiply (1) by 3 and (2) by 2. And add both the 

equations.

Adding 29y=29⇒y=2929=121y−6x=−98y+6x=38

Substitute the value of x in equation (1), we have

7(1)−2x=−3

x=5

Answer: x=5 and y=1

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Answer 2

Answer:

I hope the answer is x 5 and y 1