Question

solve the following pairs of linear equation by the substitution method
3x+4y=-1
2x+y=1​

Answer 1

Answer:

2x+y=1(1)

3x−4y=18(2)

y=1−2x.from (1)

putting value of y in (1)

⇒3x−4(1−2x)=18

⇒3x−4+8x=18

⇒11x=22

⇒x=2

Using value of x

⇒4+y=1

⇒y=−3

Answer 2

Answer:

2x+y=1(1)

3x−4y=18(2)

y=1−2x.from (1)

putting value of y in (1)

⇒3x−4(1−2x)=18

⇒3x−4+8x=18

⇒11x=22

⇒x=2

Using value of x

⇒4+y=1

⇒y=−3

Answer 3

Answer:

2x+y=1(1)

3x−4y=18(2)

y=1−2x.from (1)

putting value of y in (1)

⇒3x−4(1−2x)=18

⇒3x−4+8x=18

⇒11x=22

⇒x=2

Using value of x

⇒4+y=1

⇒y=−3