Solve the following pairs of linear equation by the method of substitution, elimination and cross multiplication
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Voll 0.20 a LTE KB/s 4G 20:27 17 a1 = 8, b, = 5 az = 3, b, = 2, 2 =- 4 %3D %3D and %D By cross-multiplication method, 1 a,b, – bzb, {(5)(-4)-(2)(-9)} {(-9)(3)–(-4)(8)} 1 {8×2-3×5} 1 -2 1 1 and 1 or, %3D -2 1 - 2 and y = 5. Y = %3D By substitution method : npa 3x = 4- 2y 4-2y From eqn. (ii), %3D or, ...(ii) 3
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