Question

Solve the following pairs of linear equations by substitution method :
( 1 ) 3x + 2y = 4 ; 4x - y = -13.
( 2 ) 2x + 3y = 20 ; 3x + 4y = 25.
( 3 ) 3x + 4y = 0 ; x - 5y = 19
please solve it and only in substitution method​

Answer 1

Answer:

Hope this answer helps you

Answer 2

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✯Solve the following pairs of linear equations by substitution method :

$\huge \bold{answer \pink \dagger}$

$\: \: \: \bf{(1) \: 3x + 2y = 4 \: and \: 4x - y = - 13 \: }$

$\: \: \\ \mapsto \displaystyle \tt{ 3x + 2y = 4}...(1)$

$\: \: \mapsto \displaystyle \tt{4x - y = - 13}....(2)$

$\: \: \\ \star \displaystyle \tt{multiply \: in \: equation \: (2) \: by \: 2}$

$\: \: \\ \mapsto \tt { \color{red} \: we \: get \: new \: equation \: 8x - 2y = - 26}....(3)$

$\: \ \\ \mapsto \bf{adding \: both \: equation \: (1) \: and \: (3)}$

$\: \implies \bf{3x + 2y = 4}$

$\: \: \: \: \: \: \bf{8x - 2y = - 26}$

$\: \: \implies \bf{11x = - 22}$

$\: \: \implies \bf{x = - 2}$

$\heartsuit\boxed{ \sf{substitute \: in \: equation \: (1)}}$

$\: \: \bf{we \: get \to \: 3( - 2) + 2y = 4}$

$\: \: \to \bf { - 6 + 2y - 4 = 0}$

$\: \: \to \bf{ 2y = 10}$

$\: \ \: \to \bf{y = 5}$

$\: \clubsuit\underline{ \boxed{ \sf \color{brown} \ \: \:solution \: are \: x = - 2 \: and \: y = 5}}$

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