Solve the following pairs of linear equations using method of elimination by substitution. 2x-3y+6=0 and 2x+3y-18=0
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2x-3y=-6. (1)
2x+3y=18. (2)
(1) + (2)
2x-3y+2x+3y=-6+18
4x. =12
x. = 3
Substitutin x=3 in equation 2
We get
6+3y=18
3y=18-6
y=4
2x+3y=18. (2)
(1) + (2)
2x-3y+2x+3y=-6+18
4x. =12
x. = 3
Substitutin x=3 in equation 2
We get
6+3y=18
3y=18-6
y=4
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