Math, asked by mridul8943, 1 year ago


solve the following pairs of linear (simultanec
ubstitution:
8x + 5y = 9
3x + 2y = 4
1.
II
II
2x – 3y = 7
5x + y = 9
2x + 3y = 8
2x = 2 + 3y
4.
0-2x + 0.1y = 25
2(x - 2) - 1.6y = 116
6x = 7y + 7
- x = 8
y = 4x - 7
16x - 5y = 25
2x + 7y = 39
3x + 5y = 31
8.
1.5x + 0.1y = 6.2
3x - 0.4y = 11.2​

Answers

Answered by padmaakalivilibadri
0

Step-by-step explanation:

all you can solve on your own ok I didn't said everything is easy you just right on your own

Attachments:
Answered by anshu8004
0

Answer:

x=-2

y=5

Step-by-step explanation:

8x+5y=9...(1)

3x+2y=4.. (2)

multiply by 3 in equation 1 and 8 in equation 2 for balancing the equation

3(8x+5y=9)

8(3x+2y=4)

we get

24x+15y=27

24x+16y=32

-. -. -

-y=-5 then y=5

putting the value of y in equation 1

8x+5*5=9

8x=9-25

8x=-16

x=-2

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