Question

solve the following pairs of linear
(simultaneous) equations using method of elimination by substitution
8x + 5y = 9
3x + 2y = 4​

Answer 1

⭐Solution⭐

✏given here

8x +5y = 9.......(1)

3x +2y = 4........(2)

[Solve by substitution method]

by (2),

3x = 4-2y

=>x = (4-2y)/3......(3)

keep in (1),

we get,

8 × (4-2y)/3 +5y = 9

=> 32-16y + 15 = 27

=> -16y = 27-47

=> y = 20/16

=> y = 5/4

keep in (3),

x = (4-2×5/4)3

= (4-5/2)/3

= (8-5)/6

= 3/6

= 1/2

✒Thus:-

Value of x = 1/2

value of y = 5/4

✏Hopes its help's u.

Answer 2

Answer:

$8x + 5y = 9 \\ 3x + 2y = 4 \\ \\ 24x + 10y = 36 \\ 2(12x + 5y) = 36 \\ 12x + 5y = 18 \\ \frac{12x}{12} + \frac{5y}{12} = \frac{18}{12} \\ x + \frac{5y}{12} + \frac{3}{2} \\ x = \frac{5y}{12} - \frac{3}{2} \\ x = \frac{10y - 6}{12} = 12x - 10y + 6 = 0$

yarr questions krta krta mind off ho gya sorry....

pls mark as the brainlist

Step-by-step explanation:

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