Math, asked by pichachushock025, 1 year ago

Solve the following pairs of simultaneous equations 31x + 37y = 25 and 37x + 31y = 43

Answers

Answered by divya2826
6

Answer:

31x+37y=25 equation first

37x+31y=43 equation second

combining equation first and second we get

-6x+6y=-18

-6(x-y) =-18

x-y=3

x=3+y

-y=3-x

Answered by lalit99992
9

Step-by-step explanation:

31x+37y=25..... (1)

37x+31y=43..... (2)

Adding (1) and (2)

68x+68y=68

x+y=68..... (3)

Subtracting (1) from (2)

-6x+6y= -18

-x+y= -18..... (4)

Adding (3) and (4)

2y=68-18

2y=50

y=50/2

y=25

Put y=25 in (3)

x+y=68

x+25=68

x=68-25

x=43

Therefore,

x=43 and y=25 is the solution of given simultaneous equations.

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