Question

solve the following pattern ​

Answer 1

Solution :

$1² + 2² + 2² → 3²$

$2²+3²+6²→7²$

$3²+4²+12²→13²$

So in these three given clues we can see that :

1 × 2 brings up 2

So, 1² + 2² + 2² → 3²

Similarly 2 × 3 = 6

So after adding square to each we get

2² + 3² + 6² → 7²

${4}^{2} + {5}^{2} + \boxed{ {20}^{2}} \rarr 441 = \boxed{{21}^{2} }$

${5}^{2} + {6}^{2} + \boxed{ {30}^{2} } \rarr961 = \boxed{{31}^{2} }$

In the last we have to multiply 6 with such a number that can given the squared number just above that

So 6 can be multiplied by 7 as we have seen earlier that 2 is multiplied by 3, 4 multiplied by 5 so here the pattern comes

that 2 and 3, 4 and 5, 6 and 7

${6}^{2} + \boxed{ {7}^{2}} + \boxed{ {42}^{2}} \rarr 1869 = \boxed{{43}^{2} }$

Answer 2

when u drive the car forward from the initial point it is positive and just drive the car reverse i.e. backwards to the initial point to get the dispacement negative. Displacement is zero when you go a round from the initial point and reach the same point.... example when the road is in a circle shape