solve the following please
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5) C) 1/7
A non-leap year has 365 days.
In 365 days, there are 52 weeks and 1 day
In 52 weeks, the number of Sundays will be 52.
1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
We can have any one of these days out of 7 days
Hence, out of these 7 outcomes, the favourable outcome is 1
Therefore, the Probability of getting 53 Sundays in a non-leap year = 1 / 7.
6) a) 1/3 (in the pic)
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