solve the following please
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Step-by-step explanation:
given A=( 1,-2) B= (2,3) C =(-3,2)&D =(-4,-3)
using distance formula
AB = √( x2-x1)^2 + (y2-y1)^2
AB= √(2-1)^2+( 3+2)^2
AB=√1+25
AB= √26
similarly BC =√(-3-2)^2+(2-3)^2
Bc= √25+1
BC = √26
similarly CD = √(-4+3)^2+(-3-2)^2
CD= √1+25
CD = √26
and DA= √(1+4)^2+(-3+2)^2
DA = √ 25+1
DA= √26
Hance all the side are equal so it is rhombus .
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