Solve the following:
please answer it will be appreciated
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Answer:
In ΔBAP and ΔCAP
∠BAP = ∠CAP --- (AD is the bisector of ∠BAC)
AP = AP -- (common)
∠BPD + ∠BPA = ∠CPD + ∠CPA = 180° (Linear Pair)
∠BPD = ∠CPD
⇒ ∠BPA = ∠CPA
Therefore,
ΔCAP ≅ ΔBAP ---(ASA criteria)
Hence Proved!!
Hope it helps u Army!!!
Purple u!!
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