Question

Solve the following pls my test is theit☝️☝️​

Answer 1

-10. ............................

Answer 2

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

Given:

• $x - \dfrac{1}{4}*\left(x - \dfrac{2 - x}{6}\right) = \dfrac{2x + 8}{3} - 3$

To find:

• Value of x.

Solution:

$\implies x - \dfrac{1}{4}*\left(x - \dfrac{2 - x}{6}\right) = \dfrac{2x + 8}{3} - 3$

$\implies x - \dfrac{1}{4}*\left(\dfrac{6x - 2 + x}{6}\right) = \dfrac{2x + 8 - 9}{3}$

$\implies x - \dfrac{7x - 2}{24} = \dfrac{2x - 1}{3}$

$\implies \dfrac{24x - 7x + 2}{24} = \dfrac{2x - 1}{3}$

$\implies \dfrac{17x + 2}{8} = 2x - 1$

$\implies 17x + 2 = 16x - 8$

$\implies<strong> </strong><strong>x = -10 </strong>$

HOPE IT HELPS!!!