Question

Solve the following :-
Plz answer correctly

Answer 1

Question 4:

• Sum of two numbers is 162.If one exceeds the other by 12,find the numbers.

Answer:-

✮ The numbers are 75 and 87 ✮

Step-by-step explanation:

Given: Sum of two numbers is 162.If one exceeds the other by 12.

To find: The numbers

According to the Question:-

❍ Let the one number be x and the other number be x + 12 respectively.

Then,

$\\ :\implies\sf{x + x + 12 = 162}\\ \\ :\implies\sf{2x + 12 = 162} \\ \\ :\implies\sf{2x = 162 - 12} \\ \\ :\implies\sf{2x = 150} \\ \\ :\implies\sf{x = \frac{ \cancel{150}}{ \cancel{2}}} \\ \\ :\implies\underline{ \boxed{ \frak{x = 75}}} \: \blue{ \bigstar}$

Therefore,

• x = 75
• x + 12 = 75 + 12 = 87

• Hence,The numbers are 75 and 87.

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Question 5:

• The ages of A and B are in the ratio 8:9.five years later,the sum of their ages will be 95 years.what are their present ages.

Answer:-

✮ The present ages of A is 45 and B is 50 ✮

Step-by-step explanation:

Given: The ages of A and B are in the ratio 8:9.five years later,the sum of their ages will be 95 years.

To find: Present ages of A and B

According to the given condition:-

❍ Let the present age of A be 8x years and B be 9x years respectively.

• 5 years later,
• Age of A = 8x + 5
• Age of B = 9x + 5

$\\ :\implies\sf{8x + 5 + 9x + 5 = 95} \\ \\ :\implies\sf{17x + 10 = 95} \\ \\ :\implies\sf{17x = 95 - 10} \\ \\ :\implies\sf{17x = 85} \\ \\ :\implies\sf{x = \frac{ \cancel{85}}{ \cancel{17}}} \\ \\ :\implies \underline {\boxed{\frak{x = 5}}} \: \pink{ \bigstar}$

Therefore,

• Present age of A = 8x + 5 = (8×5) + 5 = 40 + 5 = 45 years
• Present age of B = 9x + 5 = (9×5) + 5 = 45+5 = 50 years

Hence,

• Present ages of A and B are 45 and 50.