solve the following problem
Answers
Given :-
- A wire which resembles as a square of side 22cm is rebent in the form of circle.
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To find :-
- Radius of circle formed
- Which figure will have more area
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Solution :-
Since length of wire remains same in both figures: square and circle, so we can take their perimeter as equal. We will solve the question on this concept and also use concept of area.
So let's began by finding radius of circle!
⇒ Perimeter of circle=Perimeter of square
Now here, applying formula:
• Perimeter of circle=2πr
• Perimeter of square=4×Side
⇒ 2πr=4×Side
Substituting value of side of square
⇒ 2πr=4×22
Now transporting variable (radius) and numerical values on different sides.
Substituting value of π
By solving it we get:
So the required value of radius is 14cm.
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- Now finding which figure encloses more area:
~For square
Area of square=Side²
Area of square=(22cm)²
Area of square=484cm²
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~For circle
Area of circle=πr²
Area of circle=22/7×(14cm)²
Area of circle=22/7×196cm²
Area of circle=22×28cm²
Area of circle=616cm²
So the given wire will enclosed more area in the form of circle.
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ɢɪᴠᴇɴ :-
- side of square = 22 cm
- perimeter of square = perimeter of circle
ᴛᴏ ғɪɴᴅ :-
- radius of circle = ?
- which shape encloses more area ?
sᴏʟᴜᴛɪᴏɴ :-
- perimeter of square = 4 × side
- = 4 × 22 cm = 88 cm
- perimeter of circle = perimeter of square
- 2 π r = 88 cm
Now,
- Area of square = side × side
- = 22 × 22 cm²
- = 484 cm²
And,
- Area of circle = π r²
- =
So,
- radius of circle = 14 cm
- circle encloses more area than square