Question

solve the following problem ​

Answer 1

[ a 3 ] [ 2 b] [ 1 1 ] [ 5 0 ]

[ 4 1 ] + [ 1 -2] - [-2 c ] = [ 7 3 ]

=> [ (a + 2 + 1) (3 + b - 1) ] [ 5 0 ]

[ (4 + 1 + 2) (1 - 2 - C) ] = [ 7 3 ]

so, we can say

(a + 2 - 1) = 5

(3 + b - 1) = 0 &

(1 - 2 - C) = 3

so, by solve this we get,

a = (5-1) = 4

b = (0-2) = -2

C = (-1+3) = 2