Question

solve the following problem ??​

Answer 1

1)

At given point (1,2),we have x=1 and y=2. So, first put the value of x in the above stated problem. It will be

(1)^2 +y^2 +(1)y-y=0

1+y^2 +y - y =0

1+y^2=0

y^2 =-1

So,

y=square root of - 1

And, y=(-1)square root of - 1

2)

Equation of tangent to any curve is given by:

y=mx+c

m is slope of the curve i.e. derivative of the curve

And same would be the equation of normal but there would be a slight difference. That difference would be of the slope.

If Slope of tangent line on the curve is m then for normal line, slope would be (-1)/m.

Solve ahead yourself. If you feel any difficulty then I am here to help you.