Question

Solve the following problem. Be sure to show all steps (V.E.S.T.) and work in order to receive full credit. The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers.

Answer 1

Answer:

Answer:    x+2x+(2x+6)=26

                 x+2x+2x= 26-6

                5x=20

                x=20/5

                x=4

                First number=x=4

                Second number=2x=2(4)=8

                Third number=2x+6=2(4)+6=8+6=14

Step-by-step explanation:

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Answer 2

Given: The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second.

To find: The numbers.

Solution:  

Let the three numbers be x, y and z. According to the question, the sum of these three numbers is 26.

$x + y + z = 26$

Now, the second number is equal to two times the first number and the third number is 6 more than the second.

$y = 2x$

$z = y + 6$

  $= 2x+6$

Hence, all three numbers can be added in terms of x and equated  to 26.

$(x) + (2x) + (2x + 6) = 26$

$5x + 6 = 26$

$5x = 20$

$x = 4$

Thus, the second and the third number can be calculated as

$y = 2x$

  $= 2(4)$

  $= 8$

$z = y +6$

  $= 8+6$

  $= 14$

Therefore, the numbers are 4, 8 and 14.