Math, asked by Anonymous, 1 month ago

Solve the following problems.
1) Yusuf is 24 years older than half of Ajay's age. Five years ago, their total age was 41 years, so take their present age.

with full step by step exampletion.​

Answers

Answered by nikitaroylairik
25

Answer:

Let the present age of Ajay be x years.

According to question, Yusuf's age is 24 years older than half of Ajay's age.

Hence, Present age of Yusaf = (1x/2 + 24) years

Now, 5 years ago , Ajay's age = x - 5

5 years ago , Yusaf's age = 1x/2 + 24 - 5

= 1x/2 + 19

It's given that five years ago , sum of their ages was 41 years.

Therefore,

x - 5 + 1x/2 + 19 = 41

→ x + 1x/2 + 19 - 5 = 41

→ 3x/2 + 14 = 41

→ 3x/2 = 41 - 14

→ 3x/2 = 27

→ x = 27 × 2/3

→ x = 18

So, Ajay's age = 18 years

Yusaf's age = 1x/2 + 24

= 1× 18/2 + 24

= 9 + 24

= 33 years

Answered by hparve80
0

Answer:

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