Question

Solve the following problems.​

Answer 1

Answer:

1) (5/2)^5 / 2/5)^3

=(5^5/2^5)/ (2^3/5^3) [Distributing 5 and 3 in 1st and 2nd]

=5^5/2^5 * 5^3/2^3 [Changing position and making divide into multiply ]

=5^5*5^3/2^5* 2^3

=5^5+3/2^5+3 [Base are same so in multiply there will be plus]

=5^8/2^8

=(5/2)^8[Using rule of indices]

2) a^4 * b^5* c^7/c^8 * a^4 * b^3

=a^4-4 * b^5-3 * c^7-8 [ using rule of indices ]

=a^0 * b^2 * c ^-1 [a^0 = 1]

=1 * b^2 *c^-1