solve the following problems
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Answer:
(3p + 4g)3
Comparing (3p + 4q)³ with (a +
b)³ we have 3p and b = 4q (a + b)³ = a³ + 3a²b + 3ab² +
=
b2
(3p + 4q)3 = (3p)3 + 3(3p)²(4q) +3(3p) (4q)2 + (4q)³
= 33p3 + 3(9p²) (4q) + 9p(16q²)
- 4³q³
X 27p3 + 108p²q +144pq³.
64g3
Answered by
1
Step-by-step explanation:
(2/3x)²-2(2/3x)(3/4y)+(3/4y)²
4x²/9-xy+9/16y²
(2/3x-3/4y)²
4x²/9xy+9/16y²
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