Question

Solve the following problems by simplex method:
1. Max. z = 5x + 3x2 subject to:
3x, + 5x2 < 15
5x, + 2x2 < 10
X1, X2 20.
[IAS (M
[Ans. x, = 20/ 19, X2 = 45/ 19, Max. z =
3. Max. z = 5x + 7X2 subject to:
4
x + X2 < 4
3x, - 8x2 = 24​

Answer 1

Answer:

Confused question

Step-by-step explanation:

I can't understand

Answer 2

may be my answer helps you

Max Z or min Z = c1 x1 + c2 x2 + … + cn xn. 3.

Constraints (Inequalities). These are ... 8x1 + 4x2 = 80 passes through (0, 20) and (10, 0) ... Example 15 Solve the L.P.P. by simplex method.