solve the following problems (solution is a must)
1. If x²+4x+k=0 has two unequal real roots,what should be the value/s pf k?
2. If kx²-6x+4=0 has no real roots, what should be the values of k
3. Find a quadratic equation whose roots are the opposites of those for 6x²+7x-20=0
4. Find k so that the sum of the roots of kx²-x+7=0 is ½
5. If the product of the roots of kx²+3x+(k+2)=0 is 2, find the value of k.
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Answer:
3rd sum answer is 25/24
4th sum answer is 12
5th sum answer is 8
Step-by-step explanation:
for doing the sum please be believe in yourself then it will be easy to do this sum the sum will be looked at as very tough but it is too easy
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