Question

solve the following quadratic equatioequations by factorization x²+6x+5=0 and 8x²-22x-21=0 and 9x²-3x-2=0​

Answer 1

Step-by-step explanation:

$=> x^2+6x+5=0\\x^2+x+5x+5=0\\x(x+1)+5(x+1)=0\\(x+1)(x+5)=0\\x=-1,-5 \\\\ => 8x^2-22x-21=0\\8x^2-28x+6x-21 = 0 \\ 4x(2x-7)+3(2x-7) = 0\\ (4x+3)(2x-7) = 0\\ x = \frac{-3}{4},\frac{7}{2} \\\\ =>9x^2-3x-2=0\\9x^2-6x+3x-2=0\\3x(3x-2)+1(3x-2)=0\\(3x-2)(3x+1)=0 \\x=\frac{2}{3},\frac{-1}{3}$