Question

solve the following quadratic equatiom 2x²-8√2x+16=0​

Answer 1

Step-by-step explanation:

2x² - 8√2x+16=0

2x² -8√2x=0-16

2x² -8√2x=-16

2x² = -16+8√2x

x² = -16+8√2x

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2

x² = 0

x=0

Answer 2

Answer:

x = 2√2, 2√2

Step-by-step explanation:

= 2x² - 8√2x + 16 = 0

= 2x² - (4√2 + 4√2)x + 16 = 0

= 2x² - 4√2x - 4√2x + 16 = 0

= 2x(x - 2√2) - 4√2(x - 2√2) = 0

= (2x - 4√2)(x - 2√2) = 0

Now, for values of x:-

Case 1:

= 2x - 4√2 = 0

= 2x = 4√2

= x = 4√2 ÷ 2

= x = 2√2

Case 2:

= x - 2√2 = 0

= x = 2√2