Question

solve the following quadratic equation 0.3x²+10x+7.3=0​

Answer 1

Answer:

I hope this helps you

Step-by-step explanation:

$0.3 {x}^{2} + 10x + 7.3 = 0$

$multiplying \: by \: 10$

$3 {x}^{2} + 100x + 73 = 0$

$here \: \: \: a = 3 \: \: \: \: b = 100 \: \: \: \: c = 73$

${b}^{2} - 4ac = {100}^{2} - 4 \times 3 \times 73$

$= 10000 - 876$

$= 9124$

$x = \frac{ - b \frac{ + }{ } \sqrt{ {b}^{2} - 4ac} }{2a}$

$x = \frac{ - 100 \frac{ + }{} \sqrt{9124} }{2 \times 3}$

$x = \frac{ - 2 \times 50 \frac{ + }{} 2 \sqrt{2281} }{6}$

$x = \frac{2( - 50 \frac{ + }{} \sqrt{2281}) }{6}$

$x = \frac{ - 50 \frac{ + }{} \sqrt{2281}}{3}$

$x = \frac{ - 50 + \sqrt{2281} }{3} \: \: or \: \: \: x = \frac{ - 50 - \sqrt{2281} }{3}$