Solve the following quadratic equation:- 1 −3 + 2 −2 = 8 ; ≠ 0, 2, 3
Answers
Answered by
1
Answer:
⇒
x−3
1
+
x−2
2
=
x
8
⇒
(x−3)(x−2)
(x−2)+2(x−2)
=
x
8
⇒
x
2
−2x−3x+6
x−2+2x−6
=
x
8
⇒
x
2
−5x+6
x+2x−8
=
x
8
⇒
x(3x−8)
3x−8
=
x
8
⇒ x(3x−8)=8(x
2
−5x+6) (by cross multiplying)
⇒ 3x
2
−8x=8x
2
−40x+48
⇒ 8x
2
−3x
2
−40x+3x+48=0
⇒ 5x
2
−32x+48=0
Simplyfing above equation
⇒ 5x
2
−20x−12x+48=0
⇒ 5x(x−4)−12(x−4)=0
⇒ (5x−12)(x−4)=0
Therefore x=4
or
x=
5
12
Answered by
1
Step-by-step explanation:
Answer is 1 -3 +2 -2 = 8
8 = -2
8 + 2 = 10
hope it will use to u
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