Question

solve the following quadratic equation: 15y²-225y+840=0​

Answer 1

Answer:

8, 7

Step-by-step explanation:

15y^2 - 225y + 840 = 0

a = 15

b = - 225

c = 840

D = b^2 - 4ac

   = ( - 225 )^2 - 4 ( 15 ) ( 840 )

   = 50625  - 50400

D = 225

x = ( - b ± √D ) / 2a

  = ( - ( - 225 ) ± √225 ) / 2 ( 15 )

  = ( 225 ± 15 ) / 30

  = ( 225 + 15 ) / 30 , ( 225 - 15 ) / 30

  = 240 / 30 , 210 / 30

x = 8, 7