Solve the following quadratic equation:
2x^2 + 4x - 8 = 0
Answers
Answered by
0
Step-by-step explanation:First, let's divide all terms by 2
2
2
x
2
−
4
2
x
+
8
2
=
0
x
2
−
2
x
+
4
=
0
Let's add and subtract 1:
x
2
−
2
x
+
1
−
1
+
4
=
0
so that the initial three terms represent the square of
(
x
−
1
)
(
x
−
1
)
2
+
3
=
0
that's equivalent to:
(
x
−
1
)
2
=
−
3
but this equation has no real solution, because a square is not negative
Answered by
1
Step-by-step explanation:
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