Question

solve the following quadratic equation (2x+3)^2=25​

Answer 1

Answer:

1    or    - 4

Step-by-step explanation:

4x^2 + 9 +12x=25

4x^2 +12x - 16=0

4x^2 +16x-4x -16 =0

4x(x+4) -4(x+4)=0

(4x-4)(x+4)=0

4x-4 =0    or     x+4 =0

x=1     or      x=-4  

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Answer 2

Answer:

${(2x + 3)}^{2} = 25 \\ 2x + 3 = \sqrt{25} \\ 2x + 3 = 5 \\ 2x = 5 - 3 \\ \\ 2x = 2 \\ x = 2 \div 2 = 1$