Question

solve the following quadratic equation 2x²+31x+2=0

Answer 1

$2 {x}^{2} + 31x + 2 = 0 \\if \: a =2 \\ b = 31 \\ c = 2 \\ by \: shreedharacharya \: method \\ x = \frac{ - b + \sqrt { {b}^{2} - 4ac } }{2a} \\ = \frac{ - 31 + \sqrt{ {31}^{2} - 4(2)(2)} }{2(2)} \\ = \frac{ - 31 + \sqrt{961 - 16} }{4} \\ = \frac{ - 31 + \sqrt{945} }{4} \\ x = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ = \frac{ - 31 - \sqrt{ {31}^{2} - 4(2)(2)} }{2(2)} \\ = \frac{ - 31 - \sqrt{961 - 16} }{4} \\ = \frac{ -31 - \sqrt{945} }{4}$

Answer 2

The roots are
61.7/4
0.3/4