Question

Solve the following quadratic equation.

√3 x

2 + √2 x – 2√3 =0​

Answer 1

Answer:

$\sqrt{3}x^{2} + \sqrt{2}x - 2 \sqrt{3} = 0 \\x^{2} + \sqrt{ \frac{2}{3} }x - 2 = 0 \\ (x + \frac{1}{ \sqrt{6} })^{2} = \frac{13}{6} \\ x + \frac{1}{ \sqrt{6} } = + - \sqrt{ \frac{13}{6} } \\ x = + - \sqrt{ \frac{13}{6} } - \frac{1}{ \sqrt{6} } \\ x = \frac{ + - \sqrt{13} - 1 }{ \sqrt{6} }$

Hope it will help you