Solve the following quadratic equation.
√3x^2+ √2 x – 2√3 =0
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Step-by-step explanation:
a=√3 , b=√2 , c= 2√3
b^2-4ac= (√2)^2-4×√3×2√3
= 2-4√3×2√3
=2-8×3
=2-24
=22
x=-b+-√b^2-4ac\ 2a
=-√2+-√22\ 2√3
=2(√2+-√22)\ 2√3
ans =√2+√11\ √3 or √2-√11\ √3
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