Question

solve the following quadratic equation 3x²-x-10=0​

Answer 1

The question is wrong and will reach infinite value.

The correct question will be:-

x²-3x-10=0

Solution:-

=> x² + 2x - 5x - 10=0

=> x(x + 2) - 5(x + 2)

=> (x + 2)(x - 5) = 0

=> x + 2 = 0

=> x - 5 = 0

=> x = -2or5

.

.

Hope this helps you.

If so then please mark me as the brainliest.

:)

Answer 2

Answer:

The roots of $\tt{3x^2-x-10=0}$ are:

• $\tt{\dfrac{-5}{3}\:and\:2}$

Step-by-step explanation:

Given:

• A quadratic equation: 3x²-x-10=0

To find:

• Find the roots of the quadratic equation.

★ Concept :-

Here, we are going to solve the given quadratic equation and we are going to find the two roots of the quadratic equation. Generally, A quadratic equation can be solved through three methods:

• Factorisation Method
• Completing the square method
• Quadratic Formula

As the method is not mentioned to solve the quadratic equation in the question, we will solve the equation by factorisation method, as it is easier than the other two.

Let's solve it!!

$\tt{:\implies 3x^2-x-10=0}$

✪ Here, we are going to split the middle term(-x).

-x can be written as -6x+5x

Where, if we add it, (-6x+5x) we will get the middle term(-x) and if we multiply, we will get -30x²

$\tt{:\implies 3x^2-x-10=0}$

$\tt{:\implies 3x^2-6x+5x-10=0}$

Now, let's take 3x and 5 as common factors.

$\tt{:\implies 3x(x-2)+5(x-2)=0}$

$\tt{:\implies (3x+5)(x-2)=0}$

$\tt{:\implies 3x+5=0\:and\:x-2=0}$

$\tt{:\implies 3x= -5\:and\:x=2}$

$\boxed{\green{\tt{:\implies x= \dfrac{-5}{3}\:and\:x=2}}}$

Hence, the quadratic equation is solved.