solve the following quadratic equation 4^x+1 - 3.2^x-1 +2 = 0
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Given : 4ˣ⁺¹ - 3* 2ˣ⁺¹ + 2 = 0
To find : Value of x
Solution:
4ˣ⁺¹ - 3* 2ˣ⁺¹ + 2 = 0
Let say 2ˣ⁺¹ = y
=> 4ˣ⁺¹ = (2²)ˣ⁺¹ = (2ˣ⁺¹)² = y²
=> y² - 3y + 2 =0
=> y² - y - 2y + 2 = 0
=> y(y - 1) - 2(y - 1) = 0
=> (y - 1)(y - 2) = 0
=> y = 1 or y = 2
2ˣ⁺¹ = 1
=> 2ˣ⁺¹ = 2⁰
=> x + 1 = 0
=> x = - 1
2ˣ⁺¹ = 2
=> 2ˣ⁺¹ = 2¹
=> x + 1 = 1
=> x = 0
x =0 or x = -1
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Answer:
wrong answer you should know the steps of doing maths
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