Solve the following quadratic equation: (4/x) -3 = 5/(2x+3).
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Given :(4/x) -3 = 5/(2x+3).
(4- 3x/ x) = 5/(2x+3).
(4 - 3x) (2x+3) = 5 × x
[By cross multiplication]
12 - x -6x² = 5x
12 - x -5x -6x² = 0
12 - 6x -6x² = 0
-6(x² + x -2)= 0
x² + x -2= 0
x² +2x -x -2= 0
x(x+2)-1(x+2)= 0
(x- 1) (x + 2) = 0
(x- 1) = 0 or (x + 2) = 0
x = 1 or x = -2
Hence, -2 and 1 are the roots of the given equation.
HOPE THIS WILL HELP YOU..
(4- 3x/ x) = 5/(2x+3).
(4 - 3x) (2x+3) = 5 × x
[By cross multiplication]
12 - x -6x² = 5x
12 - x -5x -6x² = 0
12 - 6x -6x² = 0
-6(x² + x -2)= 0
x² + x -2= 0
x² +2x -x -2= 0
x(x+2)-1(x+2)= 0
(x- 1) (x + 2) = 0
(x- 1) = 0 or (x + 2) = 0
x = 1 or x = -2
Hence, -2 and 1 are the roots of the given equation.
HOPE THIS WILL HELP YOU..
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