Solve the following quadratic equation: 5x2 – 2ax – 3a2 = 0
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Given equation is 5x2 – 3x – 2 = 0. ⇒ 5x2 – 3x – 2 = 0. ⇒ 5x2 – 5x + 2x – 2 = 0 ⇒ 5x(x – 1) + 2(x – 1) = 0 ⇒ (5x + 2)(x – 1) = 0 Now, either 5x + 2 = 0 ⇒x = −25−25 Or, x -1= 0 ⇒x = 1 Thus, the roots of the given quadratic equation are 1 and x = −25−25 respectively.
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