Question

solve the following quadratic equation 6-x-x^2=0

Answer 1

$\underline{\textbf{Given:}}$

$\mathsf{6-x-x^2=0}$

$\underline{\textbf{To find:}}$

$\textsf{Roots of the given quadratic equation}$

$\underline{\textbf{Solution:}}$

$\mathsf{Consider,}$

$\mathsf{6-x-x^2=0}$

$\textsf{This can be written as,}$

$\mathsf{x^2+x-6=0}$

$\mathsf{x^2+3x-2x-6=0}$

$\mathsf{x(x+3)-2(x+3)=0}$

$\mathsf{(x-2)(x+3)=0}$

$\mathsf{x-2=0\;\;\;(or)\;\;\;x+3=0}$

$\mathsf{x=2\;\;\;(or)\;\;\;x=-3}$

$\therefore\textbf{Solution set is}\;\{\bf\,2,-3\}$

Answer 2

Answer:

$\tt x = 2 \: \: or \: \: x=3$

Step-by-step explanation:

We have,

$\tt 6-x-x^2=0$

$\tt x^2+x-6=0$

$\tt x^2+3x-2x-6=0$

$\tt x(x+3)-2(x+3)=0$

$\tt (x+3)(x-2) =0$

$\tt x = 2 \: \: or \: \: x=3$