Math, asked by rocketwomannasa, 10 months ago

Solve the following quadratic equation: 6x2+12x-8ax -16a = 0

Answers

Answered by acekaplayer

Answer:

x=-2 or x=4a/3

Step-by-step explanation:

6x²+12x-8ax-16a=0

6x(x+2)-8a(x+2)

(6x-8a)(x+2)

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Answered by XxMissPaglixX

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$6 {x}^{2} + 12x - 8ax - 16a = 0 \\ 6x(x + 2) - 8a(x + 2) = 0 \\ (x + 2)(6x - 8a) = 0 \\ x + 2 = 0 \: \: and \: \: 6x - 8a = 0 \\Now,\\ x = - 2 \: \: and \: \: (6 \times - 2) = 8a \\ x = - 2 \: \: and \: \: a = \frac{ - 12}{8} = \frac{ - 3}{2}$

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