solve the following quadratic equation 9 x2-6b2x-(a4-b4)=0
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Answer:
Step-by-step explanation:
Factorization is a bit complex instead you can use quadratic formula,but as you have asked so:
9x²-6b²x-(a^4-b^4)=0
9x²-3(2b²)x-(a^4-b^4)=0
9x²-3(b²-a²+b²+a²)x+(b^4-a^4)=0
9x²-3(b²-a²)x-3(b²+a²)x+(b²+a²)(b²-a²)=0
3x(3x-b²+a²)-(b²+a²)(3x-b²+a²)=0
(3x-b²-a²)(3x-b²+a²)=0
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