Question

solve the following quadratic equation by complete square method X square + 2 x minus 5 equals to zero​

Answer 1

Given equation is

${x}^{2} + 2x - 5 = 0$

Taking 5 to LHS

${x }^{2} + 2x = 5$

Adding and subtracting 1 to get perfect square

${x}^{2} + 2x + 1 - 1 = 5$

${x}^{2} + 2x + 1 = 5 + 1$

${(x + 1)}^{2} = 6$

Taking square root on both sides

$(x + 1) = \sqrt{6}$

$x = \frac{ + }{ } \sqrt{6} + 1$

This leaves us with two values for x

$x = 1 + \sqrt{6}$

or

$x = 1 - \sqrt{6}$

Thia is the final answer.

Answer 2

hey mate

here is the answer

if you satisfied plz mark it as brainlist answer