Question

Solve the following quadratic equation by completing the square method. ​

Answer 1

Answer:

Two solutions of quadratic equation are

y=(√2+2)/3 and y=(-√2+2)/3

Step-by-step explanation:

Given: 9y^2-12y+2=0

Step 1: Using square method,

=>9y^2-12y+2=0

=>9y^2-12y=-2

=>(3y)^2-2(3y)(2) = -2

Step 2: Adding 2^2 to both sides

=>(3y)^2-2(3y)(2)+2^2 = -2 + 2^2

=>(3y-2)^2=2

Case 1: 3y-2=√2

y=(√2+2)/3

Case 2: 3y-2= -√2

y=(-√2+2)/3

Solution :Two solutions of quadratic equation are

y=(√2+2)/3 and y=(-√2+2)/3

Answer 2

I hope it will help you

Just understand it, it is really easy